602. Friend Requests II: Who Has the Most Friends

In social network like Facebook or Twitter, people send friend requests and accept others' requests as well.

Table request_accepted holds the data of friend acceptance, while requester_id and accepter_id both are the id of a person.

| requester_id | accepter_id | accept_date|
|--------------|-------------|------------|
| 1            | 2           | 2016_06-03 |
| 1            | 3           | 2016-06-08 |
| 2            | 3           | 2016-06-08 |
| 3            | 4           | 2016-06-09 |
Write a query to find the the people who has most friends and the most friends number. For the sample data above, the result is:
| id | num |
|----|-----|
| 3  | 3   |
Note:
• It is guaranteed there is only 1 people having the most friends.
• The friend request could only been accepted once, which mean there is no multiple records with the same requester_id and accepter_id value.

Explanation:
The person with id '3' is a friend of people '1', '2' and '4', so he has 3 friends in total, which is the most number than any others.

Follow-up:
In the real world, multiple people could have the same most number of friends, can you find all these people in this case?

• b'
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Solution

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Approach: Union requester_id and accepter_id [Accepted]

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Algorithm

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Being friends is bidirectional, so if one person accepts a request from another person, both of them will have one more friend.

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Thus, we can union column requester_id and accepter_id, and then count the number of the occurrence of each person.

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select requester_id as ids from request_accepted\nunion all\nselect accepter_id from request_accepted;\n
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Note: Here we should use union all instead of union because union all will keep all the records even the \'duplicated\' one.

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Taking the sample as an example, the output is:

\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
ids
1
1
2
3
2
3
3
4
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Then it will be fairly easy to get the \'ids\' with most occurrence using the same technique as mentioned in problem 580. Customer Placing the Largest Number of Orders.

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MySQL

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select ids as id, cnt as num\nfrom\n(\nselect ids, count(*) as cnt\n   from\n   (\n        select requester_id as ids from request_accepted\n        union all\n        select accepter_id from request_accepted\n    ) as tbl1\n   group by ids\n   ) as tbl2\norder by cnt desc\nlimit 1\n;\n
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'